I talked to a few folks afterwards, and it seems there is some general confusion about the memstoreTS (and MVCC) and how it relates to the explicit timestamp stored with each KeyValue.
The key difference is that the timestamp is part of the data model. Each KeyValue has a rowkey, a column identifier, a value... and a timestamp.
An application can retrieve and set the timestamp, decide as of which timestamp(s) it wants to see a certain value, etc. It should be considered as just another part of a column (a KeyValue pair to be specific) that happens to have special meaning.
The memstoreTS on the other hand is a construct purely internal to HBase. Even though it is called a timestamp (TS), it has nothing to do with time, but is just a monotonically increasing "transaction number". It is used to control visibility (MVCC) of a "transaction" in HBase (i.e. a Put or Delete operation), so that changes are not partially visible.
Remember that the explicit timestamp is part of the application data that gets changed by a transaction.
Say you have two concurrent threads that update the same columns on the same row (a row is the unit at which HBase provides transactions):
Thread1, Put: c1 = a, c2 =b
Thread2, Put: c1 = x, c2 =y
That's cool. One of the threads will be first, HBase makes sure (via the memstoreTS) that Puts are not partially visible, and also makes sure that all explicit timestamp are set to the same value for the same Put operation.
So any client (looking at the latest timestamp) will either see (a,b) or (x,y).
Things get more confusing when a client sets the explicit timestamp of (say) a Put. Again consider this example where two concurrent threads both issue a Put to the same columns of the same row, but set different timestamps:
Thread1, Put: c1(t1) = a, c2(t2) =b
Thread2, Put: c1(t2) = x, c2(t1) =y
(t2>t1)
So what will a client see?
The first observation is still that each Put is seen in its entirety, or not at all.
If a Get just retrieves the latest versions and does so after both Thread1 and Thread2 finished it will see:
c1(t2) = x, c2(t2) = b
This is where many people get confused.
It looks like we're seeing mixed data from multiple Puts. Well, in fact we do, but we asked for only the latest versions, which include values from different transactions; so that is OK and correct.
To understand this better let's perform a Get of all versions. (i.e. call setMaxVersions() on your Get). Now we'll potentially see this:
- nothing (if the Get happens to be processed before either the Puts).
- c1(t1) = a, c2(t2) = b (Thread1 was processed first, and Thread2 is not yet finished)
- c1(t2) = x, c2(t1) = y (Thread2 was processed first, and Thread1 is not yet finished)
- c1(t1) = a, c1(t2) = x, c2(t1) = y, c2(t2) = b (both Thread1 and Thread2 finished)
In addition we can confirm that the timestamp is part of the data model that HBase exposes to clients, and the transaction visibility has nothing to do with the application controlled/visible timestamps.
Lastly in this scenario we also see that it is impossible for a client to piece together the state of the row at precise transaction boundaries.
Assuming both Thread1 and Thread2 have finished, a client can request the state as of t1 (in which case it gets c1(t1) = a, c2(t1) = y) or as of t2 (in which case it'll see c1(t2) = x, c2(t2) = b).
This behavior is the same as you'd expect from a relational database - the current state is the result of many past transactions; with the extra mental leap that the timestamp is actually part of the data model in HBase.
Hi Lars,
ReplyDeleteNice blog series. Regarding the concurrent updates and memstoreTS. I know there is a long standing problem withupdates to the same KV in the same ms that leads to more or less undefined results. Was wondering if a higher precision ts, like nanos wouldn't be a quick fix for this
Adrian
Hi Adi,
ReplyDeleteWhen using wall clock time, concurrent updates to the same cell within the same millisecond are indeed a problem.
The behavior is not really undefined, though. For two updates to the same cell in the same millisecond the last one to reach the region server will win.
Using nanoseconds would indeed help as long as the OS supports higher clock resolutions (Linux does). Also note that nano time in Java is only good for comparing relative times, not to store absolute time.
What makes this impractical, though, is the fact that that would change the storage format and that one now would need to store 16 bytes for the timestamps rather than 8.
So you're right, but it's more complicated than you might expect.
-- Lars